A= $6
B= $6+$1=$7
C= $6+$13=$19
D= $6+$15=$21
E=$6+$17= $23
F=$6+$18=$24
G= $1-$0=$1
H=$13-$1=$12
I=$15-$13=$2
J=$17-$15=$2
K=$30
L=$42-$30=$12
M=$48-$42=$6
N=$52-$48=$6
Optimal quantity is where MR=MC.
MR=MC = $12 when Q= 2.
Reason- FC is the cost which is there irrespective of the quantity. So FC=$6.
TC=TVC+TFC
MCn=TCn-TCn-1
TR=P*Q
MRn=TRn-TRn-1
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