Question

(1 point) Find the least-squares regression line y = bo + by a through the points (-3,1), (2,9), (5, 14), (9, 18), (9,24). For what value of x is y=0?

Answer 1

2 3 - 7.4 54.76 90,28 -2.4 5.76 10.08 ܐܗ 4.6 22.08 49.68 => Mx = 22 solution:s first we find least squares lieguession line 9 = botb, a where, b, = = (X-Mx) (Y-My) (X-MX) bo = My - b, Mx. Y X-MX Y- My (X-MX) (X-M) (Y-My - 3 1 -12.2 2 9 -4.2 5 14 0.6 0.8 0.36 0.48 18 4.8 21.16 9 24 4.6 10.8 21.16 Ex=22 Sy=66 E (X-Mx)? E (X-MxDCY-My) = 103.2 Mx = EX =172.6. = Mx My = 4.4 n 5 My = SY - My = Calo => My = len =) My = 13.2 co by 172.6 => b, = 1.67248. 103.2 .: a = C13.2) - (1.67248)(4.4). => Q = 5.84109 linear hegression equation, = 1.67248 X +5.84109 ->0 when ĝ=0. Now, we have to find value of x in 0. We take => 0 = 1.67248 x + 5.84109 >- 5.84109 = 1.67248 X => x = -5.84109 1.67248 => -3.4925 o enswerX = - 3.4925 00 ĝ 00

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