The thermochemical equation for the reaction is shown below:
4 Al(s) + 3 O2(g) → 2 Al2O3(s) ΔH = -3352 kJ
How much heat is released when 8.07 g of Al react with O2(g) at 25 oC and 1 atm?
Select the oxidation-reduction reaction(s)?
1. Cl2(g) + ZnBr2(aq) → ZnCl2(aq) + Br2(l)
2. Pb(ClO4)2(aq) + 2 KI(aq) → PbI2(s) + 2 KClO4(aq)
3. CaCO3(s) → CO2(g) + CaO(s)
Select the strong acid in aqueous solution from the set below.
Group of answer choices
CH3OH
HNO2
HF
HBr
A 77.0-mL sample of a 0.203 M potassium sulfate solution is mixed with 55.0 mL of a 0.226 M lead(II) nitrate solution and this reaction occurs:
K2SO4(aq) + Pb(NO3)2 (aq)
⟶⟶
⟶⟶ 2 KNO3(aq) + PbSO4(s)
The solid PbSO4 is collected, dried, and found to have a mass of 2.62 g. Determine the percent yield. 1 mole PbSO4 = 303.26 g
The thermochemical equation for the reaction is shown below: 4 Al(s) + 3 O2(g) → 2...
The thermochemical equation for the reaction is shown below: 4 Al(s) + 3 O2(g) → 2 Al2O3(s) AH - -3352 kJ How much heat is released when 8.07 g of Al react with Oz(g) at 25 °C and 1 atm? -1.68 x 104 kJ 0-104 kJ 0-754 kJ 0-2.50 x 102 kJ Which of the following processes is exothermic? o Water condensing from steam. The vaporization of water The melting of ice. O Heating water to form steam Select the...
The thermochemical equation for the reaction is shown below: 4 Al(s) + 3 O2(g) → 2 Al2O3(s) AH = -3352 kJ How much heat is released when 12.1 g of Al react with O2(g) at 25 °C and 1 atm? 0 - 104 kJ 0 -3.59 x 105 kJ -1.50 x 103 kJ O-376 kJ A 77.0-mL sample of a 0.203 M potassium sulfate solution is mixed with 55.0 mL of a 0.226 M lead(II) nitrate solution and this reaction...
A 77.0-mL sample of a 0.203 M potassium sulfate solution is mixed with 55.0 mL of a 0.226 M lead(II) nitrate solution and this reaction occurs: K2SO4(aq) + Pb(NO3)2 (aq) ⟶ 2 KNO3(aq) + PbSO4(s) The solid PbSO4 is collected, dried, and found to have a mass of 3.71 g. Determine the percent yield. 1 mole PbSO4 = 303.26 g Group of answer choices 98.4% 80.0% 120.% 75.7%
A 77.0-ml sample of a 0.203 M potassium sulfate solution is mixed with 55.0 mL of a 0.226 M lead(II) nitrate solution and this reaction occurs: K2SO4(aq) + Pb(NO3)2 (aq) + 2 KNO3(aq) + PbSO4(s) The solid PbSO4 is collected, dried, and found to have a mass of 3.71 g. Determine the percent yield. 1 mole PbSO4 = 303.26 g Hydrazine, N2H4, is a liquid used as a rocket fuel. It reacts with oxygen to yield nitrogen gas and water....
The thermochemical equation for the reaction is shown below: 4 Al(s) + 3 O2(g) → 2 Al2O3(s) ΔH = -3352 kJ How much heat is released when 12.1 g of Al react with O2(g) at 25 oC and 1 atm? Group of answer choices -3.59 × 10^5 kJ -104 kJ -1.50 × 10^3 kJ -376 kJ
Question 5 5 pts A 77.0-mL sample of a 0.203 M potassium sulfate solution is mixed with 55.0 mL of a 0.226 M lead(II) nitrate solution and this reaction occurs: K2SO4(aq) + Pb(NO3)2 (aq) - 2 KNO3(aq) + PbSO4(s) The solid PbSO4 is collected, dried, and found to have a mass of 2.62 g. Determine the percent yield. 1 mole PbSO4 = 303.26g 91.1% 120% 69.5% 80.1% Question 29 5pi If 1.85 g MgO is combined with enough 1.00 M...
A 77.0-ml sample of a 0.203 M potassium sulfate solution is mixed with 52.0 mL of a 0.214 Mlead(11) nitrate solution and this reaction occurs: K2SO4(aq) + Pb(NO3)2 (aq) 2 KNO3(aq) + PbSO4(s) The solid PbSO4 is collected, dried, and found to have a mass of 2.43 g. Determine the percent yield. 1 mole PbSO4 = 303.26g 80.1% O 120% o 58.9% o 72.0%
Select the oxidation-reduction reaction(s)? 1. Pb(ClO4)2(aq) + 2 KI(aq) → PbI2(s) + 2 KClO4(aq) 2. Cl2(g) + CuI2(aq) → CuCl2(aq) + I2(aq) 3. CaCO3(s) → CO2(g) + CaO(s) Group of answer choices 1 only 3 only 2 only 1 and 3
4. Consider the reaction of aluminum and oxygen: Al(s) + O2(g) Al2O3(s) (i). Which is the limiting reactant if we start with 30.0 g Al and 30.0 g O2? (ii). What is the Theoretical Yield for the reaction? (iii). If 25.85 g of Al2O3 was collected at the completion of the reaction (actual yield), what is the % yield for the reaction? 5. (a). A 1.506-g sample of limestone-containing material gave 0.558 g of...
Aluminum oxide (Al2O3) is produced according to the following equation. 4 Al(s) + 3 O2(g) → 2 Al2O3(s) If the reaction occurs with an 82.4% yield, what mass of aluminum should be reacted with excess oxygen to produce 45.0 grams of Al2O3? a. 54.6 g Al b. 37.9 g Al c. 35.1 g Al d. 23.8 g Al e. 28.9 g Al How do we solve this problem