Probability that the all domestic airlines will be in time = 0.84
this is a binomial distribution.
a) Probability that in the next 6 flights, exactly 4 will be on time,
b) Probability that in the next 6 flights, two or fewer will be on time,
= 0.0075
c) Probability that in the next 6 flights, at least 4 flights will be on time,
= 0.9440
d) Mean and standard deviation of the dstribution,
Mean = n*p = 6*0.84 = 5.04
Variance = n*p*(1-p) = 6*0.84*(1-0.84) = 0.8064
Standard deviation =
= 0.8980
e) Histogram of the distribution,
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