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![F. NO2 NO2 H NO2 [. for generate from H2O3 + 1,504] NO2 10 H 1-Fluoro-2-nitrobinure ( sigma complex) No2 1-Fluoro-3- útro be](http://img.homeworklib.com/questions/2d6bf150-e815-11ea-ab39-7b4ca56624e4.png?x-oss-process=image/resize,w_560)
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1. Fluorobenzene is a 0,p- director. Draw one sigma complex for...
1. Draw all the resonance forms of the sigma complex formed by nitration of p-xylene.
1. Draw all the resonance forms of the sigma complex formed by nitration of p-xylene.
1) Which of the following is an intermediate in the bromination of toluene? p) Ha BrH...
1) Which of the following is an intermediate in the bromination of toluene? p) Ha BrH 2 2) Under what reaction conditions would the electrophilic chlorination of aromatic compounds usually occur? A) Cl2, AlCl3 B) C12, CCl4 C) Cl2, H20 D) NaCl, H20 E) NaCI, CH3OH 3) 3) Which of the following is the strongest activating group in electrophilic aromatic substitution reactions? A) -CO2CH3 B)-NO2 C) -OCH3 D) -CH2CH3 E) -N(CH3)2 4) _ 4) In electrophilic aromatic substitution reactions the...
Question 3 1s 3 ORTHO Today we learned about adding a second group to a mono-substituted...
Question 3
1s 3 ORTHO Today we learned about adding a second group to a mono-substituted benzene ring. Any group on a benzene will affect the rate of the reaction (activated or deactivated relative to benzene) and the regioselectivity Where does the electrophile add? Ortho? Meta? Para? Some combination thereof? We found that EDGs (electron-donating groups) direct the electrophile to the ortho and para positions while EWGs (electron-withdrawing groups) direct the electrophile to the meta position. Now, it is time...
CHEM 3320 Practice Test 3 1 a Draw a diagram showing how the electrons would be...
CHEM 3320 Practice Test 3 1 a Draw a diagram showing how the electrons would be distributed in the pi molecular orbitals of square cyclobutadiene, and explain why this structure is anti-aromatic. (4 pts) b. Add electron pairs as appropriate and indicate whether each of these species is aromatic or not. (8 pts) 2. Consider these four benzene derivatives: CH3 Br CH3 NH2 ?. D. a. Which one would be most reactive in electrophilic aromatic substitution? (2 pts) b. Which...
1.The main product of the reaction between p-cresol and Br2 / FeBr3 is: 3-Bromo-4-methyl phenol 2-Bromo-4-methyl...
1.The main product of the reaction between p-cresol and Br2 / FeBr3 is: 3-Bromo-4-methyl phenol 2-Bromo-4-methyl phenol 2-methyl-4-bromine phenol 3-methyl-4-bromine phenol 2.Which of the following compounds is the least reactive in the nucleophilic substitution with NaOH? 2,4-dinitrochlorobenzene m-nitrochlorobenzene o-nitrochlorobenzene 3,5-dinitrochlorobenzene 3.What is the mechanism (s) for the reaction of 4-bromo-1-nitrobenzene with sodium hydroxide to form 4-nitrophenol? bimolecular nucleophilic substitution (Sn2) aromatic nucleophilic substitution by addition-elimination aromatic nucleophilic substitution by elimination-addition aromatic electrophilic substitution 4.which of the following is the correct...
Question 1 Identify all compounds below that CANNOT be made by the electrophilic aromatic substitution reactions...
Question 1 Identify all compounds below that CANNOT be made by the electrophilic aromatic substitution reactions introduced in Sections 18.1-18.6 SOH Question 2. Match each pair of structures with the appropriate term. KEY 1 = Constitutional isomers 2 - Diastereomers 0 000 3 = Different conformations 4 = Resonance structures 5 = Bond-shift isomers Question 3. In this reaction, FeBrz is acting as a and the complex that is formed will react with benzene as a/n :Br: : Br-Br: Br-Br-Fe-Br:...
(1 point) A Bernoulli differential equation is one of the form dete+ P(x)y= Q(2)y". Observe that,...
(1 point) A Bernoulli differential equation is one of the form dete+ P(x)y= Q(2)y". Observe that, if n = 0 or 1, the Bernoulli equation is linear. For other values of n, the substitution u = yl-n transforms the Bernoulli equation into the linear equation am + (1 – n)P(x)u = (1 – n)Q(x). Use an appropriate substitution to solve the equation and find the solution that satisfies y(1) = 1. y(x) =
1(a) Find the square roots of the complex number z -3 + j4, expressing your answer in the form a + jb. Hence find the roots for the quadratic equation: x2-x(1- 0 giving your answer in the form p+ q w...
1(a) Find the square roots of the complex number z -3 + j4, expressing your answer in the form a + jb. Hence find the roots for the quadratic equation: x2-x(1- 0 giving your answer in the form p+ q where p is a real number and q is a complex number. I7 marks] (b) Express: 3 + in the form ω-reje (r> 0, 0 which o is real and positive. θ < 2π). Hence find the smallest value of...
(4 points) For the tableau, P. 0 0 1 X1 5 2 -12 X2 1 1...
(4 points) For the tableau, P. 0 0 1 X1 5 2 -12 X2 1 1 -5 S1 1 0 0 S2 RHS 0 30 1 47 0 0 perform one pivot operation and enter the resulting matrix below. The pivot element has a box around it. X2 X1 S1 RHS ON
P is the (one-step) transition probability matrix of a Markov chain with state space {0, 1, 2, 3,...
P is the (one-step) transition probability matrix of a Markov chain with state space {0, 1, 2, 3, 4 0.5 0.0 0.5 0.0 0.0 0.25 0.5 0.25 0.0 0.0 P=10.5 0.0 0.5 0.0 0.0 0.0 0.0 0.0 0.5 0.5 0.0 0.0 0.0 0.5 0.5/ (a) Draw a transition diagram. (b) Suppose the chain starts at time 0 in state 2. That is, Xo 2. Find E Xi (c)Suppose the chain starts at time 0 in any of the states with...
1) Which of the following is an intermediate in the bromination of toluene? p) Ha BrH 2 2) Under what reaction conditions would the electrophilic chlorination of aromatic compounds usually occur? A) Cl2, AlCl3 B) C12, CCl4 C) Cl2, H20 D) NaCl, H20 E) NaCI, CH3OH 3) 3) Which of the following is the strongest activating group in electrophilic aromatic substitution reactions? A) -CO2CH3 B)-NO2 C) -OCH3 D) -CH2CH3 E) -N(CH3)2 4) _ 4) In electrophilic aromatic substitution reactions the...
Question 3
1s 3 ORTHO Today we learned about adding a second group to a mono-substituted benzene ring. Any group on a benzene will affect the rate of the reaction (activated or deactivated relative to benzene) and the regioselectivity Where does the electrophile add? Ortho? Meta? Para? Some combination thereof? We found that EDGs (electron-donating groups) direct the electrophile to the ortho and para positions while EWGs (electron-withdrawing groups) direct the electrophile to the meta position. Now, it is time...
CHEM 3320 Practice Test 3 1 a Draw a diagram showing how the electrons would be distributed in the pi molecular orbitals of square cyclobutadiene, and explain why this structure is anti-aromatic. (4 pts) b. Add electron pairs as appropriate and indicate whether each of these species is aromatic or not. (8 pts) 2. Consider these four benzene derivatives: CH3 Br CH3 NH2 ?. D. a. Which one would be most reactive in electrophilic aromatic substitution? (2 pts) b. Which...
Question 1 Identify all compounds below that CANNOT be made by the electrophilic aromatic substitution reactions introduced in Sections 18.1-18.6 SOH Question 2. Match each pair of structures with the appropriate term. KEY 1 = Constitutional isomers 2 - Diastereomers 0 000 3 = Different conformations 4 = Resonance structures 5 = Bond-shift isomers Question 3. In this reaction, FeBrz is acting as a and the complex that is formed will react with benzene as a/n :Br: : Br-Br: Br-Br-Fe-Br:...
(1 point) A Bernoulli differential equation is one of the form dete+ P(x)y= Q(2)y". Observe that, if n = 0 or 1, the Bernoulli equation is linear. For other values of n, the substitution u = yl-n transforms the Bernoulli equation into the linear equation am + (1 – n)P(x)u = (1 – n)Q(x). Use an appropriate substitution to solve the equation and find the solution that satisfies y(1) = 1. y(x) =
1(a) Find the square roots of the complex number z -3 + j4, expressing your answer in the form a + jb. Hence find the roots for the quadratic equation: x2-x(1- 0 giving your answer in the form p+ q where p is a real number and q is a complex number. I7 marks] (b) Express: 3 + in the form ω-reje (r> 0, 0 which o is real and positive. θ < 2π). Hence find the smallest value of...
(4 points) For the tableau, P. 0 0 1 X1 5 2 -12 X2 1 1 -5 S1 1 0 0 S2 RHS 0 30 1 47 0 0 perform one pivot operation and enter the resulting matrix below. The pivot element has a box around it. X2 X1 S1 RHS ON
P is the (one-step) transition probability matrix of a Markov chain with state space {0, 1, 2, 3, 4 0.5 0.0 0.5 0.0 0.0 0.25 0.5 0.25 0.0 0.0 P=10.5 0.0 0.5 0.0 0.0 0.0 0.0 0.0 0.5 0.5 0.0 0.0 0.0 0.5 0.5/ (a) Draw a transition diagram. (b) Suppose the chain starts at time 0 in state 2. That is, Xo 2. Find E Xi (c)Suppose the chain starts at time 0 in any of the states with...
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