Question

f 10.76 • Tarzan and Jane in the 21st Century. Tarzan has foolishly gotten himself into another scrape with the animals and must be rescued once again by Jane. The 60.0-kg Jane starts from rest at a height of 5.50 m in the trees and swings down to the ground using a thin, but very rigid, 30.0-kg vine 8.00 m long.

Answer 1

> • 200g 22 Position (1) Jane tro Couler of mousse off 3.44 / L-2 mory' I yine. Nous 7. Le mul? L8m. D B h = 55m Jane My = 60kg Tanzan - My Fly h Position 2 (onen Tarzan Jane Coues है ) here using the proportional to the triangle ů 7 8 = 2h BA ko and Ad L-h X*%* L so, the height from the ground of the Center of mass of the wine is nisi htles 2 So, the en at position 1, f t : Ko Noco, 3 2 Kine tkivine energy (strautid up = 0, Jane tu farean = might Malin - y energy Jane Ki Tangan - W7 + 2 2 2 2 2 2 the energy + 22, w,? + Reit at position U = Potantial Waz ZO ht Ei mign + mug Now, the ci mergy 2 Im. ( 2 ) 11 energy at 2 = mg (72 (ma?? (where. Wy is angular speed before is . bedo after the graly

(30x9.0) (2) (60+4,80)W By cuergy Comune rowention, 1, 12 → migut mwy (nt -: (60*9*8 *p*) + 3089-8 *(* *4->) Noud, ping Nalues and solve for me 27 (19), fra 1959 la 2 2. an W2 3 134 rad/s " Angular speed of Jame before She him 1.34 rad/s grabs WB. is the wy him, 1 angular speed after the grops him (m & m.) is the mass of Jane (mgtm.) and Tanzone angular momentom is conserved. As tuere is no net frietion, the meet forsque is zero and and the

9088 Nm 80, L2 = hy į mv 2 I 2 W2 = (my 2. L'of 407 cl Em2. MvLW2 Do (Go 10% te usor de or 3*)(131) = 6008 2. ngoma / twag = (180 + 72x82) Way 3 L3 3 = 13 W3 1 2 + m +12 2 Key rm2 S Now I r. Wm وا L3 6PoB.2.0.66 = 0.66 grads 11 9088 can the angular speed after she grabs of roll Using the proportions, A OA and ABCD ܢ from figure H2 L-d کو e A D 42 Jane ay M 2. 3 Coonen Led Taman neach iez und maximo neight by energy conservation, int key = UATKA (my stoma) 90) + mely) the - (my town) Bd+ mvoldte)

im It 30x9: 8x 4 +124088 * Corbei (60+ 72) 980+ 3498(14(4-6) 1976. + 1979.3664 =12936á+ 294 294(14) 1176 11979.3. = 1440*60 +1176 1440:6 1: 3 73 m the height have to be acheived 1.373 m 7 da 1979.3 SOM