Question

please answer both! i will upvote

7) A radio tower 500 feet tall, and the ground on one side of the tower has an inclination to the horizontal of 10 degrees while the other does not. How long should the wires be if wire sis to be connect to the top of the tower and wiret is to be connected to the middle of the tower. Both wires are secured at 1000 feet directly above and below the base of the tower? (There are two answers, one for each wire)

Answer 1

M for wire ti 2014 N LNP9 = 90-10 = poo OPO- ENPO = got10=100° zooft o loooh o toooft p 466 Using Cosine seule in ANPO, (No)² = (NP)²+(po) ² - 2 (NP) (po) Cos Lupo - @502 + (000-2 (250) (100) Cos 100' = 625 00 + 1000000 500000 Cos 100 - 11493 24.08883 .: No 1149324.08883 ~/1072.06 ft similarly, using Cosine rule in DNPO, Ng? = NP²tPg² -2(WP) (P8) Co CAS CNPO = (200)+(100032 -2 (250) (1000) cos solº = 62500 + 1000000 - 500000 cod 80° = 975675.911166 i Ng = √975675 911166 1987.76 ft 21 SAS

M A ४ G a 8=6 in 60 p=2 / 2 = 23 x 180 = 120° Area of the shaded area Area of sector AB CMA Area of A ABG T8²b 28² sind = a (6) ²x120 360 12 - 18 x = 127-93 360 - }(6) Sin (120°) 3 ง 3 = 22.1106545749 22.11 in ² i b. d = BM-BN=8 h = 6 h A 6=8 8=6 h In ABNA, Cos 30° = AN = AN AB » AN=6 Cos 30° -38 x 3 = 36 6 30° 12 A C & Sin 30° = BN = 4 20 » h= 6 sin 30 = 36x 1 = 3 .: d= 6-h= 6-3 got (from ③ & 4) =/3 in a

Answers for each question is in the rectangular boxes