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A random sample of 90 days at a coffee shop produces a mean daily sales of...
The owner of a computer repair shop has determined that his daily revenue has a mean of $7000 and a standard deviation of $1200. The daily revenue totals for the next 30 days will be monitored. What is the probability that the mean daily revenue for the next 30 days will exceed $7325? A hotel chain is considering expanding into Gotham. As part of their consideration they want to estimate the average number of conference rooms rented daily. The population...
The daily demand for coffee in a coffee shop approximately has a normal distribution with mean 220 cups and standard deviation 40. Assuming that the demands in different days are independent, what is the probability that the average demand in the next five days exceeds 240? ( Hint: Sum of five independent normal variables have also a normal distribution N(220, 40^2 /5), standard deviation=sqrt(40^2 /5). Use pnorm )
A random sample of 40 cups of coffee from a vending machine had a sample mean volume of coffee dispensed equal to 7.1 oz. with standard deviation s = 0.3 oz. Find a 90% confidence interval for the population mean amount of coffee dispensed per cup.
A simple random sample of 900 elements generates a sample proportion 0.72 a. Provide the 90% confidence interval for the population proportion (to 4 decimals). b. Provide the 99% confidence interval for the population proportion (to 4 decimals). How large a sample should be selected to provide a 95% confidence interval with a margin of error of 3? Assume that the population standard deviation is 50, Round your answer to next whole number. Sales personnel for Skillings Distributors submit weekly...
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals From a random sample of 57 dates, the mean record high daily temperature in a certain city has a mean of 83.56°F. Assume the population standard deviation is 14 43°F. The 90% confidence interval is (0) (Round to two decimal places as needed.)...
A simple random sample of 90 items from a population with = 9 resulted in a sample mean of 38. If required, round your answers to two decimal places. a. Provide a 90% confidence interval for the population mean. to b. Provide a 95% confidence interval for the population mean. to c. Provide a 99% confidence interval for the population mean. to Sales personnel for Skillings Distributors submit weekly reports listing the customer contacts made during the week. A sample...
{Exercise 8.14 Algorithmic} A simple random sample with n = 56 provided a sample mean of 21.0 and a sample standard deviation of 4.5. a. Develop a 90% confidence interval for the population mean (to 2 decimals). ( 20 ®, 22 ) b. Develop a 95% confidence interval for the population mean (to 2 decimals). c. Develop a 99% confidence interval for the population mean (to 2 decimals). d. What happens to the margin of error and the confidence interval...
A simple random sample of 60 items resulted in a sample mean of 90. The population standard deviation is 13. 1) Compute the 95% confidence interval for the population mean (to 1 decimal). 2) Assume that the same sample mean was obtained from a sample of 120 items. Provide a 95% confidence interval for the population mean (to 2 decimals). 3) What is the effect of a larger sample size on the margin of error?
Mooncents Coffee Shop has just opened, and on the first 6 days of business, the number of customers who have come into the store during a particular time period are as reported in the following table. Day # Customers 1 25 2 22 3 23 4 28 5 29 6 26 a. Calculate the average number of customers visiting and the sample standard deviation of customer visits for Mooncents Coffee. (Round intermediate...
A simple random sample with n = 56 provided a sample mean of 23.5 and a sample standard deviation of 4.7. a. Develop a 90% confidence interval for the population mean (to 1 decimal). ( , ) b. Develop a 95% confidence interval for the population mean (to 1 decimal). ( , ) c. Develop a 99% confidence interval for the population mean (to 1 decimal). ( , )