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Question 3 20 pts Given the following decomposition reaction: 2503 (9) = 2502 (9) + 02 (9) Determine the value for K, as well
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Answer #1

Prepare the ICE table

SO3. SO2. O2

I]. 0.500atm. 0. 0

C]. -2X. +2X. +X

E]. 0.200atm. 2X. X

From SO3 pressure ,

0.500atm - 2X =0.200atm

2X. = 0.500atm - 0.200atm

=0.3atm

X. =0.3 / 2

=0.15

O2 = X = 0.15atm

SO2=2X= 0.3atm

SO3 = 0.200atm

Kp =[P​​​​​​2 (SO2)×P(O2)] / [P​​​​​​2 (SO3)]

=[(0.3)2 ×(0.15)] / [(0.200)2 ]

=0.0135/0.04

=0.338

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