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3. (6 points) Consider the curve y = 2 - 2.22 restricted to the first quadrant. (a) Set up a definite integral that gives the
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Givene y = 2-242 y = - 40 fo, 2) a) length= 1 +16r² du 161,0) b) Surface Area. S.A - 201 Se (2-2n? 2-24²) J 1 + 166² du * If

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