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Five people roll a 60-sided die which has labels 1, 2, ..., 60. What is the chance that all five pe different numbers? Round
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Answer #1

The first person can get a number from 1,2,..,60 in 60 ways. If the second person has to get a different number, then he must get one of the remaining 59 numbers. If the third person has to get a different number than the first two persons. then he must get one of the remaining 58 numbers and finally the fifth person can get a different number than the others in 56 ways.

Thus the number of ways the 5 persons get five different numbers is 60*59*58*57*56.

Again the chance of getting an outcome when the die is rolled five times is 605.

Then the required probability is 60*59*58*57*56/605=.843

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