Question 5 (4 points) What is the major product of the following reaction? 1. NaOET Eto...
help asap Friedel-Crafts acylation reactions cannot be performed on aniline because: The amino group attacks the Lewis acid to form an acid-base complex in which the aromatic ring is strongly deactivated. The amino group is strongly activating and multiple substitutions occur on the aromatic ring. The amino group is strongly deactivating preventing any substitution on the aromatic ring. The amino group gets acylated instead of the aromatic ring. Which of the following produces no reaction? -O'Na+ + H2O CH3 Li+...
Question 18 (4 points) Friedel-Crafts acylation reactions cannot be performed on aniline because: The amino group gets acylated instead of the aromatic ring. The amino group attacks the Lewis acid to form an acid-base complex in which the aromatic ring is strongly deactivated. The amino group is strongly activating and multiple substitutions occur on the aromatic ring. The amino group is strongly deactivating preventing any substitution on the aromatic ring.
Question 11 (4 points) What is the major product of the following reaction? 1. NaOEt ju Eto OEt 2. Hz0+ OEt Eto OH OEt O OEt o Eto 애 OEt
Question 13 (4 points) What is the common name of the compound listed below? N,N-dimethyl-N-sec-butane dimethylisobutylamine ON. N-dimethyl-2-butanamine O sec-butyldimethylamine Question 14 (4 points) Classify the structure below by Configuration, Family, Backbone, and # of Chirality Centers: CH,OH H -OH H -OH CH OH OL, pentose, ketose, 2 OD pentose, ketose, 2 OD. tetrose, aldose 3 OL. tetrose, aldose, 3
What is the major product of the following reaction? 1. NaOEt E10 ΟΕΙ 2. Hz0+ OEt Eto OH OEt
Question 18 (4 points) What is the major product of the following reaction? 1. NaOEt EIO ΟΕΙ 2. H30*
Question 3 (4 points) What is the major product of the following reaction? 8 1. NaOE EIO OEI 2. H,0 13 ΟΕΙ O 17 OEt MacBook Pro 80 F2 3 4. 5 6 7 00 9 E R. Т. Y U
Question 30 (4 points) Friedel-Crafts alkylation reactions cannot be performed on benzaldehyde because: The aldehyde group is strongly activating, and multiple substitutions occur on the aromatic ring. The aldehyde group gets alkylated instead of the aromatic ring. The aldehyde group attacks the Lewis acid to form an acid-base complex in which the aromatic ring is strongly deactivated The aldehyde group is moderately deactivating preventing any substitution on the aromatic ring. Question 31 (4 points) Which of the following produces no...
QUESTION 17 Select the major product of the following reaction scheme: Reaction NaBHA Dilute HCI EtOH, 25 °C 25 °C D CI НО OET B E Honi HO OH с EIO OEt (No Reaction) ol. A oll. B o lll.c IV.D .V. E o VI.F
Thank you! 9. What would be the product of the following conversion? 1. NaOEt, EIOH OEt 2. H,о- OEt ОН О OEt OEt OEt OE OEt e. d. 10. What is the product of the Dieckmann condensation of the following diester? 1.NaOCH, CH,Oн HgCOoc coOCHs 2. H,0* осн, COOCH COOCH b. d. both a) and b) e. a), b), and c) a. C. 11. Consider the synthesis below. What is compound X? COOEt COOH 1. КОВи 1. NAOH, H2O, heat...