Question

Question 44 10 pts For an IPv4 address: 128.171.17.12, the network part is 128, the subnet part is 171.17. What will be the network mask and subnet mask for it? Please provide the answer in both the dotted-decimal notation format and the prefix notation format. 12ptv Paragraph ~ B I U Αν Av Tv : р O words Question 45 10 pts Please simplify the address 2001:0000:0000:0000:00fe: 0000:0000:cdef

44 and 45

Answer 1

Answer 44
***********
128.171.17.12 address is from class A and default subnet mask of class A is 255.0.0.0 but the subnet part is 171.17 will change the subnet mask to 255.255.255.0 because if you perform AND operation on this address with subnet mask then you will get the network address.

128.171.17.12
255.255.255.0 AND operation
---------------
128.171.17.0

or 255.255.255.0 can also be written with slash notation which is /24 as 255.255.255.0's binary conversion is 11111111.11111111.11111111.00000000 now if you count there will be 24 1s and thats why it is /24

Answer 45
************
2001:0000:0000:0000:0000:00fe:0000:0000:cdef
2001:0:0:fe::cdef

if you have any doubt then please ask me without any hesitation in the comment section below , if you like my answer then please thumbs up for the answer , before giving thumbs down please discuss the question it may possible that we may understand the question different way and i can edit and change the answers if you argue, thanks :)