Question

Assuming an ideal op-amp in the following circuit, find output voltage, Vo if R1= 2 K12, R2=8 KN, R3=3.9 KN, R4=6 KN, R5=18 KUsing the above circuit, but consider the following component values: R1= 2 KO2 R2=8 K12, R3=3.6 K12, R4=6 K12, R5=16.9 KN, R

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Answer #1

4.4K2 (I, KIB Ig :8K2 + To VN 18K e ve 11 v=lv + 1 RL=12.5kr T=0 IS onsm A I os 33.95 36692 늘 thu 3.4V o we know for ideal

we know concept of virtual short in op-amp. So Up = VN -2.06 VN substitute Eavation ④ € Equation -2.06 -2.06 - Vo + ima- (-2.

© RG w 18K ve + (v=lv R2 6km RL 1 36k I4 V3 Dart uit Zin. By voltage divider Rule 6K Up = = -2X - 3.6K +6K V = -2x 9.6K vp= -

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