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Save & Exit 5 Let X be normally distributed with mean u = 120 and standard deviation o = 20. [You may find it useful to refer

Hele c. Find x such that PX X) = 0.40. (Round z value and final answer to 3 decimal places.) Kipped eBook eferences d. Find

Help 5 c. Find x such that PX sx) = 0.40. (Round z value and final answer to 3 decimal places.) 3.33 points Skipped eBook R

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M=120 r. 20 x < 86 X-4 Za -34 20 from standard deviation Z< -1.7 P(23-1.7) 10.0446 table A -17 =10.1359 p(805X3100) p (-2825-P(xs x) = 0.40 P ( x<z) = 0.4 using stand and curre table z = -0.253 -0.28 X zotu = -0.253 (20) + 120 = 114.940 4) p(x>x) = 0

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