Question

1.)

Describe the sampling distribution of p. Round to three decimal places when necessary. N=25,000, n=200, p = 0.6 O A. Approximately normal; Hp = 0.6, Op = 0.035 OB. Exactly normal; Hp = 0.6, p = 0.035 O C. Binomial; Hp = 120, op = 6.928 O D. Approximately normal; Hp = 0.6, Op = 0.098

2.)

3.)

To assess attitudes towards issues that affect the residents of a village, the village randomly chose 800 families to participate in a survey of life attitudes the village received 628 completed surveys what is the sample proportion of completed surveys?

0.628

0.785

1.274

0.886

Answer 1

ANSWER:

1)

Population size, N=25,000
Sample size, n= 200
Proportion, p=0.6
The mean of the sampling distribution of p is 0.6

06

standard deviation $\small \sigma _{p}$ = $\small \sqrt{p(1-p)/n}$

$\small =\sqrt{0.6(1-0.6)/200}$

$\small \sigma _{p} = 0.035$

Approximately normal $\small \mu$ _p = 0.6 _, $\small \sigma$ _p = 0.035

(option -a)

..........................

2)

n = 800

x = 628

sample proportion = x / n

= 628 / 800

= 0.785

(option - b)

...............................

3)

mean = $\small \mu$ = 74

standard deviation = $\small \sigma$ = 3

n = 36

$\small P(\overline{X}>75)= P(\frac{\overline{X}-\mu }{\sigma /\sqrt{n}} >\frac{75-74}{3/\sqrt{36}})$

P(Z > 2) = 0.0228

(option - d)

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