Question

A restaurant in a fast food franchise has determined that the chance a customer will order a soft drink is 0.93. The probability that a customer will order a hamburger is 0.58. The probability that a customer will order french fries is 0.51. Complete parts a and b below.

a. If a customer places an​ order, what is the probability that the order will include a soft drink and no fries if these two events are​ independent?

b. The restaurant has also determined that if a customer orders a​ hamburger, the probability the customer will order fries is 0.77. Determine the probability that the order will include a hamburger and fries.

Answer 1

Let S be the event that a customer will order soft drinks.
Let H be the event that a customer will order hamburger.
Let F be the event that a customer will order french fries.

Given Information

P(S) 0.93


PH 0.58


P(F) 0.51

• Here, we are to find:
  
  P(FNS
  
  
  = P(F) * PSC
  (Due to independence)
  
  =0.51 *(1-0.93
  
  
  0.0357
  
  
  Hence, the required probability is 0.0357
  
  
• Here, it is given that,
  
  P(FH) = 0.77
  
  
  We are to find:
  
  P(FNH)
  
  
  P(FH) * PH
  
  
  = 0.77 * 0.58
  
  
  =0.4466
  
  
  Hence, the required probability is 0.4466.
  
  

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