Question

The wheel rolls without slipping and has the angular velocity of 10 [rad/s] in the clockwise direction. The acceleration of point Gis 1.5 [m/s2). 0=10 [rad/s] 0.5 m B ag =1.5 [m/s?] х A Copyright © 2016 Pearson Education, Inc. All Rights Reserved (1) Determine the velocity of point A. (2) Determine the velocity of point G. (3) Determine the velocity vector of point B. (4) Determine the angular acceleration of the wheel. (5) Determine the acceleration vector of point A. (6) Determine the acceleration vector of point B.

Answer 1

given = Roll without slipping to= lo radis aer = 1.5m/s² Y = o.smes B GO + Va NPR Va - ro -ol sliding Rotatine Velocity of point a = due to pure Rolling a=omis ♡ Velocity of Cr V = ro [yor 0.5810 = smis ③ velocity of B Vo = √²+rwy? Tw=V rol ✓ 2v2 2542 [ VB = V2 55 mis ] & angular acon of whell Caue to pure rolling) oxo = a VB [d = af = 3 Rad/s2 A A 14 ra AB = s2 = a thus A = vw² = 0.5x 10² = 100x. A = so mis² Now a atrw? = 1.5+ 5o = 51.5 m/s2 & rd = Q = IS od L erw? ta JOS15P+(1.532 Q8 = 51.52M152]