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Find the forces memberZ D F A 2 m 1 m C F = 300N у 5 m E B 2 m -1.5 m

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Answer #1

consider Joint D. F 3oo N Initially assume Tension in each member FDA -Itha FA Sot - 2j 2K 3 FDB FDB 2k 51 + 1.5 √31.25 FDC -FED = – 85.7143 i + 128.5714j 171.4286K FCA ^ FEA j toj tok + FEB i + FCB Ojn + ok? FCF k FCB toj Now Joint Equilibrium at c

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