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The work required to stretch a spring 1.2 meters beyond its natural length is 36 Joules. The force required to hold the sprin

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Answer #1

=>ld Natural length of spoing is and spoing sy and constant ak 2 K x (-2) = 36. (J) 2 11 36X2 1-28102 50 - (N/M) ka 50 N/m ca

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