The work required to stretch a spring 1.2 meters beyond its natural length is 36 Joules....
Work of 8 Joules is done in stretching a spring from its natural length to 2 m beyond its natural length What is the force (in Newtons) that holds the spring stretched at the same distance (2 m beyond its natural length)? Do this problem by hand and show all your steps.
(1 point) 5 Joules of work are done when stretching a spring from it's natural length to 11 cm beyond it's natural length. What is the force (in Newtons) needed to stretch the spring 11 cm?
Differential Equation problem
We know that a force of 2.8 Newtons is required to stretch a certain spring 0.7 meters beyond its natural length. A 1.44-kg mass is attached to this spring and allowed to come to equilibrium. The mass-spring system is then set in motion by applying a push in the upward direction that gives the mass an initial velocity of 1.04 meters per second. Let y(t) represent the displacement of the mass above the equilibrium position t seconds...
if the work required to stretch a spring 2 feet beyond its
natural length is 15 ft-
Express the limit as a definite integral: 6 lim - n جn = 1+ ()4 6 da Jo =(1+24) 6 dz =(1+24) 6 dx 1 + r4 1 1+ 4 6 1 + 4 Question 3 w ity *
Suppose that 6 J of work is needed to stretch a spring from its natural length of 24 cm to a length of 34 cm. (a) How much work is needed to stretch the spring from 26 cm to 30 cm? (Round your answer to two decimal places.) J 1.52 (b) How far beyond its natural length will force of 40 N keep the spring stretched? (Round your answer one decimal place.) x cm 19.33
Suppose that 6 J of...
A 1-meter spring requires 10 Joules to stretch the spring from its unstretched length to 1.1 meters. How much work would it take the stretch the spring from a starting length of 1 meter to 1.2 meters? HTML Edita
714 Suppose that 6 ) of work is needed to stretch a spring from its natural length of 36 cm to a length of 51 cm. (a) How much work is needed to stretch the spring from 44 cm to 45 cm? (Round your answer to two decimal places.) X] (b) How far beyond its natural length will a force of 10 N keep the spring stretched? (Round your answer one decimal place.) 105.91 X cm Need Help? Read It...
Hooke’s Law states that the force required to maintain a spring stretched x units beyond its natural length is proportional to x, i.e. f(x) = kx where k is a positive constant. Suppose that 4 J of work is needed to stretch a spring from its natural length 10 cm to a length of 36 cm. Find the exact value of work needed to stretch the spring from 15 cm to 28 cm.
3) Consider Hooke's Law: The force required to keep a spring in a compressed or stretched position x units from the spring's equilibrium position is F(x)-kr Calculate the work required, in joules, to stretch a spring 0.4 meters beyond its equilibrium position for each of the following scenarios. a) The spring requires 50 Newtons of force to hold it 0.1 m from its equilibrium position. b) The spring requires 2 Joules of work to stretch the spring 0.1 meter from...
23 A spring hos a natural length of 2 feet. A force of 15 pounds is required to hold it compressed at a length of 18 inches al Assuming Hooke's Law appllo find the spring constant b) Find the force necessary to stretch the spring, Fix. c) Find the work required to stretch the spring from its natural length to a length of 3 23. A spring has a natural length of 2 feet. A force of 15 pounds is...