Question

The 88-lb force P is applied to the 200-lb crate, which is stationary before the force is applied. Determine the magnitude of the friction force F exerted by the horizontal force on the crate.

Please show complete solution.

200 lb Р ſus = = 0.50 r Up = 0.40

Answer 1

N I 7 W = 200 lb n P = 88 lb Efyo -> New force applied on the block P=88 eb The static frictional force changes its value based on how much force is being applied to the unbudging object. Es max = Mg x N = Msx W. But it has a maximum value as well 0.50 X 200 = 100 eb > P the Fomax hence the object is in rest and the frictional force F exerted on the P = 88 lb object WHY ? Because ; object is i, we now know that in rest P Rest :. If x=0 >> F= P = 88 eb w