Question

Let G be a group, and let a ∈ G. Let φa : G −→ G be defined by φa(g) = aga−1 for all g ∈ G. (a) Prove that φa is an automorphism of G. (b) Let b ∈ G. What is the image of the element ba under the automorphism φa? (c) Why does this imply that |ab| = |ba| for all elements a, b ∈ G?

9. (5 points each) Let G be a group, and let a € G. Let oa: G +G be defined by Ca(9) = aga- for all g €G. (a) Prove that , is

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Answer #1

Pa : G G by Pa (g) = agat, & GEG. Let c d E G and c= d. Then, acat-adat - Pale) - PA (d) So, la is well-defined. Now Palet)=

(b 6EG. dalba)= a(ba) at abaatab ② Let, ./gl=n. Then, (ayat) - a gra- e so, lagat)=19 | Take gaba. Then, labaal-libal => lab

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