Homework Answers
In regards to statistical hypothesis, we know--
| Reality | |||
| Positive | Negative | ||
|
Study Finding |
Positive | True Postive | Type I error(False positive) |
| Negative | Type II error(False negative) | True Negative |
a) You reject H0, when H0 is true.
Type I error
b) You do not reject H0, when H0 is false.
Type II error
c) 
You conclude not to reject that average body tempareture of 98.6o when in reality it is not 98.6o
Type II error
d) 
You conclude to reject the dropout rate is 23% when in reality it is 23%
Type I error
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Which of the following are type 1 or type 2 errors. a) You reject Ho, when...
1 of 2 (Question 1 of 2) If we fail to reject Ho when in fact...
1 of 2 (Question 1 of 2) If we fail to reject Ho when in fact He is true, this is a _ error. A Type 1 B Type II C None of the above 2 of 2 (Question 2 of 2) The mean fineness, u, of yarn is expected to be greater than the standard, value of 5 units. To test this claim, the factory graded 16 specimens of the yarn and found the sample average, X, to be...
E IV. USE THE INFORMATION BELOW TO ANSWER PROBLEMS 12-15 A simple random sample of 27...
E IV. USE THE INFORMATION BELOW TO ANSWER PROBLEMS 12-15 A simple random sample of 27 people from a diverse population have an average body temperature of 97.9 degrees with a standard deviation of 0.18 degrees. At the 1% significance level, can we conclude that the population from which the sample has a body temperature lower than the accepted 98.6 degrees? Below is the appropriate StatCrunch output for the problem. Assume that body temperature follows an approximate normal distribution. Std....
IV. USE THE INFORMATION BELOW TO ANSWER PROBLEMS 12-15 A simple random sample of 27 people...
IV. USE THE INFORMATION BELOW TO ANSWER PROBLEMS 12-15 A simple random sample of 27 people from a diverse population have an average body temperature of 97.9 degrees with a standard deviation of 0.18 degrees. At the 1% significance level, can we conclude that the population from which the sample has a body temperature lower than the accepted 98.6 degrees? Below is the appropriate StatCrunch output for the problem. Assume that body temperature follows an approximate normal distribution. Std. Dev....
It is commonly believed that the mean body temperature of a healthy adult is 98.6∘F98.6∘F. You...
It is commonly believed that the mean body temperature of a
healthy adult is 98.6∘F98.6∘F. You are not entirely convinced. You
believe that it is not 98.6∘F98.6∘F.
It is commonly believed that the mean body temperature of a healthy adult is 98.6° F. You are not entirely convinced. You believe that it is not 98.6° F. a) If you going to test this claim at the 0.01 significance level, what would be your null and alternative hypotheses? Ho: Select an...
6) For the following problems, identify the hypotheses, define Type I and Type II errors, and...
6) For the following problems, identify the hypotheses, define Type I and Type II errors, and discuss the consequences of each error. (When you set up the hypotheses, consider which is the hypothesis you are ”trying to prove”, and that is your alternative. The null hypothesis is then the status quo.) a. The FDA judges the safety of new drugs. When faced with a new drug, there are two possible decisions: approve the drug or disapprove the drug. b. You...
You may need to use the appropriate technology to answer this question. Consider the following data...
You may need to use the appropriate technology to answer this question. Consider the following data for a dependent variable y and two independent variables, x, and x, V X1 y 30 92 12 47 10 108 25 17 112 51 16 178 40 5 94 51 19 175 74 7 170 36 12 117 59 13 142 16 210 The estimated regression equation for these data is -18.74 2.01x, 4.73x Here, SST 15,229.6, SSR 14,077.25 0.2495, and 0.9575. (a)...
To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens...
To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens are buried in soil for a 2-year period. The maximum penetration (in mils) for each specimen is then measured, yielding a sample average penetration of x = 52.8 and a sample standard deviation of s = 4.3. The conduits were manufactured with the specification that true average penetration be at most 50 mils. They will be used unless it can be demonstrated conclusively that...
To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens...
To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens are buried in soil for a 2-year period. The maximum penetration (in mils) for each specimen is then measured, yielding a sample average penetration of x = 52.9 and a sample standard deviation of s = 4.3. The conduits were manufactured with the specification that true average penetration be at most 50 mils. They will be used unless it can be demonstrated conclusively that...
I'm only confused on why the P-Value is 0. I usually use my TI84 calculator and...
I'm only confused on why the P-Value is 0. I usually use my TI84
calculator and it gave me 7.354
Twenty years ago, 53% of parents of children in high school felt it was a serious problem that high school students were not being taught enough math and science. A recent survey found that 241 of 700 parents of children in high school felt it was a serious problem that high school students were not being taught enough math and...
What is normal, when it comes to people's body temperatures? A random sample of 130 human body temperatures had a mean of 98.15° and a standard deviation of 0.74°. Does the data indicate that the average body temperature for healthy humans deviates from 9
Test using the p-value approach with ? = 0.05.State the null and alternative hypothesis.H0: ? < 98.6 versus Ha: ? > 98.6H0: ? = 98.6 versus Ha: ? > 98.6 H0: ? = 98.6 versus Ha: ? < 98.6H0: ? = 98.6 versus Ha: ? ≠ 98.6H0: ? ≠ 98.6 versus Ha: ? = 98.6Find the test statistic and the p-value. (Round your test statistic to two decimal places and your p-value to four decimal places.)z=p-value=State your conclusion.The p-value is greater than alpha so H0 is not rejected. There is insufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6°.The p-value is less than alpha so H0 is rejected. There is sufficient evidence to...
1 of 2 (Question 1 of 2) If we fail to reject Ho when in fact He is true, this is a _ error. A Type 1 B Type II C None of the above 2 of 2 (Question 2 of 2) The mean fineness, u, of yarn is expected to be greater than the standard, value of 5 units. To test this claim, the factory graded 16 specimens of the yarn and found the sample average, X, to be...
E IV. USE THE INFORMATION BELOW TO ANSWER PROBLEMS 12-15 A simple random sample of 27 people from a diverse population have an average body temperature of 97.9 degrees with a standard deviation of 0.18 degrees. At the 1% significance level, can we conclude that the population from which the sample has a body temperature lower than the accepted 98.6 degrees? Below is the appropriate StatCrunch output for the problem. Assume that body temperature follows an approximate normal distribution. Std....
IV. USE THE INFORMATION BELOW TO ANSWER PROBLEMS 12-15 A simple random sample of 27 people from a diverse population have an average body temperature of 97.9 degrees with a standard deviation of 0.18 degrees. At the 1% significance level, can we conclude that the population from which the sample has a body temperature lower than the accepted 98.6 degrees? Below is the appropriate StatCrunch output for the problem. Assume that body temperature follows an approximate normal distribution. Std. Dev....
It is commonly believed that the mean body temperature of a
healthy adult is 98.6∘F98.6∘F. You are not entirely convinced. You
believe that it is not 98.6∘F98.6∘F.
It is commonly believed that the mean body temperature of a healthy adult is 98.6° F. You are not entirely convinced. You believe that it is not 98.6° F. a) If you going to test this claim at the 0.01 significance level, what would be your null and alternative hypotheses? Ho: Select an...
You may need to use the appropriate technology to answer this question. Consider the following data for a dependent variable y and two independent variables, x, and x, V X1 y 30 92 12 47 10 108 25 17 112 51 16 178 40 5 94 51 19 175 74 7 170 36 12 117 59 13 142 16 210 The estimated regression equation for these data is -18.74 2.01x, 4.73x Here, SST 15,229.6, SSR 14,077.25 0.2495, and 0.9575. (a)...
To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens are buried in soil for a 2-year period. The maximum penetration (in mils) for each specimen is then measured, yielding a sample average penetration of x = 52.8 and a sample standard deviation of s = 4.3. The conduits were manufactured with the specification that true average penetration be at most 50 mils. They will be used unless it can be demonstrated conclusively that...
To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens are buried in soil for a 2-year period. The maximum penetration (in mils) for each specimen is then measured, yielding a sample average penetration of x = 52.9 and a sample standard deviation of s = 4.3. The conduits were manufactured with the specification that true average penetration be at most 50 mils. They will be used unless it can be demonstrated conclusively that...
I'm only confused on why the P-Value is 0. I usually use my TI84
calculator and it gave me 7.354
Twenty years ago, 53% of parents of children in high school felt it was a serious problem that high school students were not being taught enough math and science. A recent survey found that 241 of 700 parents of children in high school felt it was a serious problem that high school students were not being taught enough math and...
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