Question

Eight houses are lined up on a street, with four on each side of the road as shown: Each house wants to set up its own wi-fi

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Answer #1

(a) The graph can be visualized as follows :

1 2 8 7 6 5

(i) Each house is represented by the vertex in the graph. Two vertex (houses) have an edge in between if there is WiFi interference. This happen when the two houses are either adjacent or they are just on the directly opposite sides of the road.

(ii) The problem reduces to the Graph Coloring Problem : we need to find the minimum number of colors required so that the graph can be vertex colored i.e.. any two vertices with a common edge should different colors. This minimum number of colors is also called as chromatic number. Then, number of different WiFi-channels required = Chromatic Number of the Graph.

(b) The solution to this problem is 2. So, we need exactly 2 different WiFi-channels so that everybody can have WiFi without interference. The solution is shown below :

1 2 8 7 6 5

Houses 2,4,6,8 can have WiFi on the one channel whereas Houses 1,3,5,7 can have WiFi on second channel. So, total WiFi channels required = 2.

(c) The edge conditions need to be updated as per the question. Each house remains a vertex and now edges are between adjacent houses and houses which are directly opposite to each other on the road and left and right of the opposite house. The updated Graph is shown below :

8 7 6 5

Again we need to color the vertices of the graph with minimum colors so no two vertices that share an edge should gave the same color. This can be done using 4 colors as shown below:

2 7 6 5

Hence, the number of WiFi-channels required is 4. Vertices with the same color can share the same channel. (1,3) will share first channel, (2,4) can share the second channel, (6,8) can share the third channel and (5,7) can share the fourth channel.

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