Problem 4 (10 points) Calculate the overall reliability of the following system (show calculation to receive...

Question

Question

Answer 1

Answer #1

B2 = 0.90 R1 = 0.95 R2 = 0.95 R3 = 0.95

Since R2 and B2 are parallel, the resultant reliability, R2' = 1 - (1 - R2)*(1 - B2) = 1 - (1 - 0.95)*(1 - 0.90) = 0.995

R1 = 0.95 R2 = 0.995 R3 = 0.95

Now, R1, R2', and R3 are in series, so, the overall reliability of the system = R1 * R2' * R3 = 0.95*0.995*0.95 = 0.8980

Answer 2

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