2.- (25) Find I 3213 D , 20v 20 30 2 Dz 212
{ 2.- (25) Find I I, 321 D 20v 212 2 DZ 322 III o
* please answer step by step. Problem # 1 (20 pts.) A. Given For the circuit: 12 12 20V+ 2Ω B. Determine Step 1: Find the equivalent resistance seen by the 20 V source Step 2: Find the value of the current lo. Step 3: Find the power generated by lo as it passes thru the indicated 2 resistor Problem # 1 (20 pts.) A. Given For the circuit: 12 12 20V+ 2Ω B. Determine Step 1: Find the equivalent...
2290° A 220 V -1512 4Ω8 {j3 n © 320 Find the SAE's for the assigned loop currents. Solve for the loop currents. Round answer to 2 decimal places, add O's as needed. Express magnitude as positive number and angle between 180° .A N Z • А 2 • A
A 220 Ω 1/2 w resistor has burned open, so you look in your parts box to find a replacement, which one of the following resistors could you use to repair the circuit? 220 Ω 114 w 2200 Ω 1/2 w 220 Ω 1/8w 22001w
Integration by substitution 1. Find each of the following indefinite integrals using integration by substitution: dz (a) / (xºcos(x4) ) do (c) / (sin(2) cromka) die (e) / (24) do (a) / (2.eller) die (0) / (zlog.cz) Integration by parts 2. Find each of the following indefinite integrals using integration by parts: (a) / (+cos(x)) dx (c) / (vVy + 1) dy (e) / (sin”(w) ) at (8) / (sin(o) cos(0) ) da (b) / (x2=+) di (a) / (x2108_(2))...
use the chain rule to find dz/ds and dz/dt. z=arcsin(x-y), x=s^2+t^2, y=2-6st. dz/ds=? dz/dt=?
20 (1) dz 20! x 10 7 5 z100 (2) e dr 100! x 10 3 20 (1) dz 20! x 10 7 5 z100 (2) e dr 100! x 10 3
Find! ! dz where C : |2|-l , clockwise Find zexp()dz where C is from to z- i along the axks Find! ! dz where C : |2|-l , clockwise Find zexp()dz where C is from to z- i along the axks
Find the differential of the function. z = 7t- - 1 / 1 7 +2 dz = Submit Answer