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1 1 2 1 0 3 -3 6 1. (a) Bring the matrix A = -1 2-5 5 to the echelon form. Find a basis for the 2 1 5 0 image and the kernel

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a 1 A- R37 R₂ th I 2 1 o 3 -3 6 - 2 5 5 0 Ry - Ry-2R, 1 2 1 0 3 -36 0 3 -36 -11 2 0 B7R2/3 R3-) Rz - R2 Ryt Ry + R2 2 -12 1 21st Row say 2020/07 End Row 4+ y + 213 tolyo Row say u-13 tayo - ų = 13-224 4 =-34 +8 by I dz 1-30 tbly U₂ -28y 13 ny wy (7)

Part B is just definition of eigen vector

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