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A pendulum consisting of a uniform rod and concentrated mass at its free end is pivoted to the inertial frame through a revol

Use Reaction forces and Energy methods. Please show all working. Thank you very much.

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M ma Solution- 3 kg M-5 t-1.2 m 5 kg Img vmg T= loo N-m [ACW] T no 1] Moment of Inertia for rod and concentrated mass = I= me x= dw dt dw.do do dt w du do . w dw11.574 - 8.8562 caso do at 60° 60- IT 3 WO at Q = 300° W- W 300°: 5 TT cules 5/3 Gurdw :By the condition of equillibrium Fx po Rc = (m mw? + MW? 4) sin 30 2 Ra = (m + M) Wed sin 30 ( 3+5) Ra (11-2978)2 x (1-2) Sin

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