Question

A survey conducted during the pandemic showed that 1726 out of 1961 residents of Letter Town and 2118 out of 2615 residents of Kenny Town wore a mask. Assuming the data from the two towns are independent, use a 0.10 significance level to test the claim that a higher percentage of residents in Letter town wore a mask. Round your answer to 3 decimal places p-value=0.810, evidence not support claim Op-value 0.840, evidence not support claim p-value-7.106, evidence support claim p-value=0.000, evidence support claim p-value-0.880, evidence support claim

Answer 1

62 = 2118, 12=2615 Sol Null hypothesis). Ho: Pi =Pz ie., two towns of residents equally wore a mask. Alternative hypothesis. Ha: P, > P2 i.C., higher percentage of residents in tetter town wore a mask. Criven values are n = 1961, X, = 1726. P = proportion of residents of Letter Town 1726 ni = 0.8802. 1961 P = x, ΥΣ P2 = proportion of residents of kenny Town P2 = x2 2118 = 0.8099 2615 Test stalStc). Z- Pi-P2. ~NCOD) Poltto) where Kitty P= (1726+2118) ntna = 0184, P = 0.16 1961 +2615 iz= 0. 8802-08099 | (084)(0-10)( 198 + P-value. The p-value is 0.0000 Conclusions since the p-value is less than then we reject Ho. Hence we conclude that higher percentage of residents in letter town wore a mask. (evidence support cains) = 6+4193 2015 2/2010