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A sample of 25 observations is selected from a normal population where the population standard deviation is 20 and the sample
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Answer #1

Given , sample size = n = 25

Sample mean T = 120

Population standard deviation = \sigma = 20

We have to find lower limit of confidence interval.

Formula :

Lower limit =

T - 2a/2 X n

Where ,  -a/2  is critical value for given confidence level  

Confidence level = 70% = 0.7

Significance level = \alpha = 1 - 0.7 = 0.3 ,  \alpha/2 = 0.15

So, critical value is ,  -a/2 = 0.15 = 1.0364 ----> Using Excel function , "=NORMSINV(1-0.15)"=1.0364

Therefore, Lower limit of 70% confidence interval is given by,

Lower limit = 120 - 1.0364*(20/25 )

Lower limit = 120 - 4.1456

Lower limit =115.854

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