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Question 2 1/1 pts 5% of a certain population has a particular genetic condition. A test for this condition gives a positive
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Answer #1

Let, A be an event that denotes that a population has a particular genetic condition.

B be an event that denotes that test shows positive result.

We have, P(A) = 0.05

P(B) = 0.20

P(B|A) = 0.99

Now, we have to calculate the probability, P(A|B) = ?

As, P(B|A) = P(A∩B)P(A)=0.99P(ANB) P(A) = 0.99

i.e. PA∩B=0.99×0.05=0.0495P(ANB) = 0.99 X 0.05 = 0.0495

Therefore, P(A|B) =PA∩BPB=0.04950.2=0.24750.0495 P(ANB) P(B) = 0.2475 0.2

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