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9-15. Locate the centroid of the shaded area. Solve the problem by evaluating the integrals using Simpsons rule. =0

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Answer #1

Let's consider a strip at distance x from origin of width dx. Further solution is given below-

0.5e A poset Sada SIA А ñ= n ty 0 co.se-y) y+o.se 2 dy= o.se-o.se dA= dax (o.se-o-sen) Sa. Co-se-o-sendu x= 6 Scoise-0.5 en a.

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