Question

30 Using the following equation determine the average concentration (moles per liter) of acetic acid (CH,CO,H) present in your vinegar. Record the concentration in Data Table 2 average volume of NaOH (mL) X 1L NAOH 1000 mL NAOH 0,5 mol NaOH 1. NaOH 1 mol CH4COH 1 mol NaOH = average moles of CH,CO,H average moles of CH,CO,H 5.0 ml, vinegar 1000 ml IL = Concentration of CH.CO, H (M=mol/L) 31 Using the following equation and your result from Step 30, determine the percent concentration (mass percent) of acetic acid (CH,CO2H) in the vinegar and record it in Data Table 2 Note: The moll of acetic acid is from the calculated concentration of acetic acid from the above equation, the density of vinegar is 1.006 g/mL., and the molecular mass of CH,CO,H is 60.06 g/mol average mole of CH.COH 1 L vinegar x IL 1000 ml 1 ml vinegar 1.006 g vinegar X 60,05 g CH,COH 1 mol CH.COH * 100% = Average mass percent of CH,CO,H (96)