Use back-substitution to solve the system of linear equations. (If there is no solution, enter NO...

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Question

Use back-substitution to solve the system of linear equations. (If there is no solution, enter NO...

Use back-substitution to solve the system of linear equations. (If there is no solution, enter NO SOLUTION. If the system is dependent, set z = a and solve for x and y in terms of a.)

6x − 5y + z	=	52
−y + z	=	11
z	=	6

(x, y, z) =

math algebra

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Answer 1

Answer #1

Solution given system of equations 6N-5y + 2 = 52 - Y + 2 = 11 2 = 6 2 3 using back. substitution. from equation ③ Z=6 y valu

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Answer 2

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