Question

3 A study of seat belt users and nonusers yielded the randomly selected sample data summarized in the accompanying table. Use a 0.05 significance level to test the claim that the amount of smoking is independent of seat belt use. A plausible theory is that people who smoke are less concerned about their health and safety and are therefore less inclined to wear seat belts. Is this theory supported by the sample data? B Click the icon to view the data table. - X More Info Hy: The amount of smoking is not independent of seat belt use. OD. Ho: Heavy smokers are not less likely than non-smokers to wear a seat belt. Hy: Heavy smokers are less likely than non-smokers to wear a seat belt. Number of Cigarettes Smoked per Day 0 1-14 15-34 35 and over Wear Seat Belts 178 24 47 9 Determine the test statistic. Don't Wear Seat Belts 145 17 38 13 x2 = (Round to three decimal places as needed.) Print Determine the critical value. Use a 0.05 significance level to test the claim that the an Done less concerned about their health and safety and are therefore less inclined to wear se O A. There is not sufficient evidence to reject the claim that heavy smokers are less likely than non-smokers to wear a seat belt. The theory is supported by the sample data. O B. There is sufficient evidence to reject the claim that the amount of smoking is independent of seat belt use. The theory is not supported by the sample data. OC. There is sufficient evidence to reject the claim that heavy smokers are less likely than non-smokers to wear a seat belt. The theory is supported by the sample data. are

Answer 1

The null and alternative hypotheses are: C) Ho: The amount of smoking is independent of seat belt use. H1: The amount of smoking is not independent of seat belt use. The test statistic is: x2 = 1.965 Critical value = 7.815 Conclusion: D) There is not sufficient evidence to reject the claim that the amount of smoking is independent of seat belt use. The theory is supported by the sample data.

Chi-Square Tests df Value 1.965 لا أنا 3 3 Asymp. Sig. (2-sided) .580 581 .508 Pearson Chi-Square Likelihood Ratio Linear-by-Linear Association 1.959 .439 1 N of Valid Cases 471 a. O cells (0.0%) have expected countless than 5. The minimum expected count is 9.95.