HC2H3O2(aq) + NaHCO3(s) --> CO2(g) + H2O(l) + NaC2H3O2(aq)
please help balance!
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HC2H3O2(aq) + NaHCO3(s) --> CO2(g) + H2O(l) + NaC2H3O2(aq) please help balance!
Measuring Enthalpy Results NaHCO3(s) + HC2H3O2(aq) à NaC2H3O2(aq) + H2O(l) + CO2(g) Trial 1 Trial 2 mass of baking soda(NaHCO3) added 5.4g 5.4g mass of vinegar added 20ml 20ml Final temperature, tf 16.7C 16.7°C Initial temperature, ti 21.1°C 21.1°C Change in temperature, ∆t 4.4°C 4.4°C q (water) = mwCwTw 467.6 J 467.6 J q(reaction) -467.6 J -467.6 J moles of NaHCO3 .0642 .0642 ΔH (kJ/mol) -7.27448 kJ/mol -7.27448 kJ/mol Complete questions using data from table and the answer from question...
1) Classify the following reaction by reaction type HC2H3O2(aq) + NaOH(aq) → NaC2H3O2(aq)+ H2O(l) is a(n) __________________ reaction
1. Consider the reaction: NaHCO3(aq) + HCl(aq) → NaCl(aq) + CO2(g) + H2O(l) Question: 0.056 moles of NaHCO3 are reacted with excess HCl. 2.267 g of CO2 were produced. What is the percent yield of CO2?
A. When a 3.28 g sodium bicarbonate tablet was dissolved in vinegar, 0.68 g of CO2 was produced. Use the stoichiometry NaHCO3(aq) + HC2H3O2(aq) → CO2(g) + H2O(l) + NaC2H3O2(aq) to calculate the amount (moles) of NaHCO3 consumed. B. Assume all the NaHCO3 consumed originated from the tablet. Calculate the mass of NaHCO3 in the tablet. C. Based on your answer on B, calculate the mass percent on NaHCO3 contained in the tablet.
Complete and balance the following equations. 1)CO2(g)+OH−(aq) 2)NaHCO3(s)+H+(aq) 3)CaO(s)+C(s) 4)C(s)+H2O(g) 5)CuO(s)+CO(g)
Excess NaHCO3(s) is added to 535 mL of Cu(NO3)2(aq) 0.240 M for the reaction Cu(NO3)2(aq)+2NaHCO3(s)→CuCO3(s)+2NaNO3(aq)+H2O(l)+CO2(g). a)How many grams of NaHCO3(s) the will be consumed? b)How many grams of CuCO3(s) will be produced?
Possible Chemical Equations NaHCO3 (s) → NaOH (s) CO2(g) NaHCO3 (s) → Na2CO3(s) + CO2(g) + H2O(g) NaHCO3 (s) → Na2O(s) + CO2(g) + H2O(g) NaHCO3 (s) → Na(s) + H2(g) + C(s) + O2(g) Conclusions: 1. Rewrite and balance each of the four chemical equations from the lab introduction.
Possible Chemical Equations NaHCO3 (s) → NaOH (s) CO2(g) NaHCO3 (s) → Na2CO3(s) + CO2(g) + H2O(g) NaHCO3 (s) → Na2O(s) + CO2(g) + H2O(g) NaHCO3 (s) → Na(s) + H2(g) + C(s) + O2(g) Conclusions: 1. Rewrite and balance each of the four chemical equations from the lab introduction.
Classify the following as acid-base reactions or oxidation-reduction reactions. (a) 3 HClO4(aq) + Fe(OH)3(s) → Fe(ClO4)3(aq) + 3 H2O(l) (b) HC2H3O2(aq) + NaHCO3(aq) → NaC2H3O2(aq) + CO2(g) + H2O(l) (c) 4 H2O(l) + 2 KMnO4(aq) → 2 MnO2(s) + 2 KOH(aq) + 3 H2O2(aq) (d) Cl2(g) + KOH(aq) → KClO(aq) + HCl(aq) (e) 2 Fe(s) + 3 NaOCl(aq) → Fe2O3(s) + 3 NaCl(aq) (f) CaC2(s) + 2 H2O(l) → C2H2(g) + Ca(OH)2(s) Explain your reasoning
****** Balance all of the following equations******* Part A Na2CO3(aq)+HCl(aq)→NaCl(aq)+H2O(l)+CO2(g)Na2CO3(aq)+HCl(aq)→NaCl(aq)+H2O(l)+CO2(g) Express your answer as a chemical equation. Identify all of the phases in your answer. Part B Submit Request Answer HgO(s)→Hg(l)+O2(g)HgO(s)→Hg(l)+O2(g) Express your answer as a chemical equation. Identify all of the phases in your answer. Part C Submit Request Answer Fe(s)+O2(g)→Fe2O3(s)Fe(s)+O2(g)→Fe2O3(s) Express your answer as a chemical equation. Identify all of the phases in your answer. Part D Submit Request Answer Na(s)+Cl2(g)→NaCl(s)Na(s)+Cl2(g)→NaCl(s) Express your answer as a chemical equation....