Question

4.

Find the 8th term of the geometric sequence whose common ratio is 3 2 and whose first term is 7. 8 х 5 ?

5.

6

7

8.

Answer 1

4 pa 3% a=7 toa cue knoo B-1 an = 7x(36)7 15309 128 5 and team tz = ag ag'= "781 let 4=a. a8 12 - 33 Q12 = ? Aga = arr apra 481 as= an = 33. 3 5 - 8 = -3548) 5 s T pa 3. a = Il 81x9 a 12 i ar U 981 * (~33" - 2673

6 ay - 1 an 5- 4 an-te. n2 -> A = u + 2 F-4X(-1) +2 = 442-6 n=3 =) Az = -4a2+2= - 4X6 + 27- 2472 = -22 Mp4 au = 88+2 - 40g +2 -4X (-22) + 2 = 290 A ..25-1, Q2 =6, az=- 22, aurao F Let the equation of Panabola be (2-8)" =40(y + 4) de a = 11-4 =8 Youll .:- (2-3) = 8,46 %+4) DO The distance betauen focus and directrix is Ha (1, 2) 341=4. ga= 4 910-9 a=2. are The Co-ondinates of B are (-3,-2) The Co-ordinates of vertex (-37, -272) = (-1,-2) The equation of Parabola is (4+2)"= 4.2(a+I) 51(702) * 8(7121)