A normal population has a mean of 60 and a standard deviation of 12. You select...

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Answer 1

Answer #1

$Given~:~\mu=60~;~\sigma=12~;~n=9$

$Standard~ error~(SE)=~\sigma/\sqrt{n}$

$SE=~12/\sqrt{9}$

SE=~12/3

SE=~4

Standard~error~of~the~mean~is~4.

Answer 2

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