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An astronomer is interested in measuring in light years, the distance from his observatory to a distant star. If the astronom

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Solution :

standard deviation = \sigma = \sqrt{} 4 = 2

Z\alpha/2 = Z0.025 = 1.96  

sample size = n = [Z\alpha/2* \sigma / E] 2

n = [1.96 * 2 / 0.5]2

n = 61.46

Sample size = n = 62

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