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Question 2: Identify which of Cases (1)--(4) apply to the following LP problem. max z = 2x1 – X2 s. t. X1 – X2 < 1 2x1 + x2 >

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Max 2 = 2x, x2 2,-0, < Bubject to : 2%, +*> 6 , , x2 > 0 12,-X₂= 2x, + X2 = 6 and 21 0 27 3 016 X2 -1 1X2 Note: Identifying tWe see comer ave We at corner Occur pornsts (vertices) of feasible region (0,6) and (5) poists So evaluating points, z(0,5) -

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