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DETAILS LARLINALG8 7.3.033. Show that any two eigenvectors of the symmetric matrix A corresponding to distinct eigenvalues ar
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A-[13] 43 23 Solution Given A=133 33 DI-A= -3 3 3 d-3 III- Al= 3 - (+372-9. 3 2-3 II - Al=0 > (2-3)²-9-o d²+9-6d-9=0 d (d-6)=Hence Eigen vector Xi and X2are -> -32,+ 322 30 and 3*, *3*2=0. Let 22= t.. Then. 32,-3tro 32,=t -) 게 Hz) taso eigen vector N

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