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A system of equations was written as an augmented, which was row reduced to: [1 0 0 0 0 1 0 - 4 0 0 1 4 What is the solution to the original system of equations? 2 = 2= Question Help: D Video D Post to forum Submit Question

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MX 1 0 o - - L 0 0 0 -4 o 4 Z 0 0 1 1,200 y = -4, 2-4 ） two distan innan d.. ir 3+492 Low reduced augmented matrix is The original system of equation is equivalent to (Fax) "The equation of a parabola with focus at (-69 -4.) and has directrix n = 5 Let , tot (2,4). be the parabola. Find the distance between (x, y, and the focus. Then find the distance between (x,y) and directrix. Egnate te these equations in x and andy is equation of the parabola. The distance between (ning and (6-4) The distan distance between (ny) and the directrix s n=$ in- ) jas Ans! any pt. m is 2 is

Equating the two distance expressions, we have, 2 tnt Let Ing ) (y + 4 fu- (0+2)+(994)*= fx- EU? z? (4+4² -&)*-(+6919 (2-3-4-43)(mer +9 - 32'( 29+16) F-37(*+8) A satellite us consider the equation of the parabola in standard form, y - tp (-nj tk, parabola is o co-ordinate of the focus is Chr+P] and the opens up no consider the parabola to with center at 10,0). Then the equation of parabola becomes y = 1 1 1 How it is given that the dish is 72 feet across its opening and a feet deep.at point on parabolen (36,9) The n2 its center, this gires a

Then. 9-tp (36)² P. 36. This the co-ordinate of the foeus in (0,36). Therefore the receiver need to be placed art (0, 36) ie. the distance between between receiver and the rol vertex is voojt (0-36] 36 feet