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Sut = 80 ksi, Sy= 60 ksi, Si = 40 ksi, q=0.85 (notch sensitivity), steel E = 30e6 psi Remember we use Modified-Goodman for alA3 inch hollow tube with 1/16 inch wall thickness is used to make a 4 foot long drive shaft. The maximum torque on the is 400

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Answer #1

​​​​​​Given -60 001 inch Diameter (0) Diameter (d) 1/16 inch 4 foot Length of shaft (L) = 48 inch 40o ft lof Man tos que exft tor q

ra ) Yield fos = yield stress stren Man Man stress Jp 400 400 x 16 TID? *(3)? 16 75.3 Mi so, 106 75-3 for fatigue loading + 0

w When there hole ? so, Yield FOC JI Max stress MN stren | ㅗ 오 TL Jp 0085 ㅠ 픕에 09 1 88 for fatigue loading 00 라 + 0.5x sut Sg

for deflection 0.002 in PL PL 0.002 TDT EX0.002 d Ae X 0:00 L P= 2.us lo sxiose So, stress (6) = de A 12.5 ksi loading This r

for reverse loading 라 syt O.Sfut 0 T- (1 을 어= 12.S 다. 1RS SI 다 OS x 80 SI N 32 CS Scanned with CamScanner

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