Homework Answers
here mean difference =134.75-108.25 =26.5
since mean difference is less than the margin of error ; there does not appear to be significant difference
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Assuming a Bonferroni margin of error of 83.66, this is regardless of your answer above, is...
6.12 Margin of error and the confidence interval. A study of stress on the campus of...
6.12 Margin of error and the confidence interval. A study of stress on the campus of your university reported a mean stress level of 78 (on a 0 to 100 scale with a higher score indicating more stress) with a margin of error of 5 for 95% confidence. The study was based on a random sample of 64 undergraduates more e. The study w (a) Give the 95% confidence interval. (b) If you wanted 99% confidence for the same study,...
Use the given confidence level and sample data to find (a) the margin of error and...
Use the given confidence level and sample data to find (a) the margin of error and (b) the confidence interval for the population mean u. Assume that the population has a normal distribution. Weight lost on a diet: 90% confidence; n 20, x= 7.0 kg, s 9.2 kg. Click the icon to view a table of critical t-values. kg (Round to one decimal place as needed.) (a) E (b) What is the confidence interval for the population mean u? kg<u...
Random samples of players for two types of video games were selected, and the mean number...
Random samples of players for two types of video games were
selected, and the mean number of hours per week spent playing the
games was calculated for each group. The sample means were used to
construct the 90 percent confidence interval (1.5, 3.8) for the
difference in the mean number of hours per week spent playing the
games. The maker of one of the video games claims that there is a
difference in the population mean number of hours per...
(6 pts) A psychologist who needs two groups of students for a learning experiment decides to...
(6 pts) A psychologist who needs two groups of
students for a learning experiment decides to select a random
sample of female college
students and male college students. Before the experiment, the
psychologist administers an IQ test to both groups to determine if
there is a significant difference in their mean IQ scores. The
population standard deviation for this IQ test is know to be
for both female and male populations. If the sample
mean IQ score of the female...
Answer the following question The level of lead in the blood was determd for a sample...
Answer the following question
The level of lead in the blood was determd for a sample of 152 male hazardous waste workers age 20-30 and also for a sample of 85 female workers, resulting in a mean t standard error of 5.3 +0.3 for the men and 3.80.2 for the women. Calculate an estimate of the Merence between true average blood lead levels formale and female workers in a way that provides information about reliability and precision (Use a 95%...
The level of lead in the blood was determined for a sample of 152 male hazardous-waste workers age 20-30 and also for a...
The level of lead in the blood was determined for a sample of 152 male hazardous-waste workers age 20-30 and also for a sample of 86 female workers, resulting in a mean standard error of 5.8 +0.3 for the men and 3.8 + 0.2 for the women. Calculate an estimate of the difference between true average blood lead levels for male and female workers in a way that provides information about reliability and precision. (Use a 95% confidence interval. Round...
An advocacy group is interested in determining if gender (1 = Female, 2 = Male) affects...
An advocacy group is interested in determining if gender (1 = Female, 2 = Male) affects executive level salaries. To this end, they took a random sample of executives in three different industries (1 = Consumer Goods, 2 = Financial, 3 = Health Care) and collected salary data. A partial two-way ANOVA table summarizing the results is provided below. Two-way ANOVA: Salary versus Industry, Gender Source MSF P Industry Gender Interaction Error Total DE SS 2 23342.6 1 4915.2 2...
In a random sample of 3,000 non-smckers, 270 suffer from heart disease and, in sample of...
In a random sample of 3,000 non-smckers, 270 suffer from heart disease and, in sample of 800 smokers, 88 suffer from heart disease. At the 0.01 level of significance, test whether the prevalence of heart disease is significantly higher in smokers as compared to non-smokers? [8 markah/marks] (b) Seorang penyelidik ingin membandingkan gaji purata penganalisis kewangan wanita dan lelaki. Seramai 25 orang penganalisis kewangan lelaki dan 16 penganalisis kewangan wanita yang dipilih secara rawak. Gaji purata dan sisihan piawai untuk...
1. ANOVA is a statistical method for verifying the equality between some sample means b. a....
1. ANOVA is a statistical method for verifying the equality between some sample means b. a. some sample standard deviations c. some population standard deviations d some population means Salary information regarding male and female employees of a large company is shown below Sample Size Male (Pop. 1) Female (Pop. 2) 49 47 Sample Mean Salary (in $1,000) , Population Variance 2. The point estimate of the difference μ-μ, between the two population means is Y 7-44-3.0 3. The margin...
answer the exibit with an explanation please Exhibit 16-1 Salary information regarding male and female employees...
answer the exibit with an explanation please
Exhibit 16-1 Salary information regarding male and female employees of a large company is shown below. Mals Female Sample Sure 36 Sample Mean Salary (in $1,000) Population Variance (0) 128 3. Refer to Exhibit 10-1. The point estimate of the difference between the means of the two populations is b. 3 C4 d 4 ANS: B 4. Refer to Exhibit 10-1. The standard error for the difference between the two means is b....
6.12 Margin of error and the confidence interval. A study of stress on the campus of your university reported a mean stress level of 78 (on a 0 to 100 scale with a higher score indicating more stress) with a margin of error of 5 for 95% confidence. The study was based on a random sample of 64 undergraduates more e. The study w (a) Give the 95% confidence interval. (b) If you wanted 99% confidence for the same study,...
Use the given confidence level and sample data to find (a) the margin of error and (b) the confidence interval for the population mean u. Assume that the population has a normal distribution. Weight lost on a diet: 90% confidence; n 20, x= 7.0 kg, s 9.2 kg. Click the icon to view a table of critical t-values. kg (Round to one decimal place as needed.) (a) E (b) What is the confidence interval for the population mean u? kg<u...
Random samples of players for two types of video games were
selected, and the mean number of hours per week spent playing the
games was calculated for each group. The sample means were used to
construct the 90 percent confidence interval (1.5, 3.8) for the
difference in the mean number of hours per week spent playing the
games. The maker of one of the video games claims that there is a
difference in the population mean number of hours per...
(6 pts) A psychologist who needs two groups of
students for a learning experiment decides to select a random
sample of female college
students and male college students. Before the experiment, the
psychologist administers an IQ test to both groups to determine if
there is a significant difference in their mean IQ scores. The
population standard deviation for this IQ test is know to be
for both female and male populations. If the sample
mean IQ score of the female...
Answer the following question
The level of lead in the blood was determd for a sample of 152 male hazardous waste workers age 20-30 and also for a sample of 85 female workers, resulting in a mean t standard error of 5.3 +0.3 for the men and 3.80.2 for the women. Calculate an estimate of the Merence between true average blood lead levels formale and female workers in a way that provides information about reliability and precision (Use a 95%...
The level of lead in the blood was determined for a sample of 152 male hazardous-waste workers age 20-30 and also for a sample of 86 female workers, resulting in a mean standard error of 5.8 +0.3 for the men and 3.8 + 0.2 for the women. Calculate an estimate of the difference between true average blood lead levels for male and female workers in a way that provides information about reliability and precision. (Use a 95% confidence interval. Round...
An advocacy group is interested in determining if gender (1 = Female, 2 = Male) affects executive level salaries. To this end, they took a random sample of executives in three different industries (1 = Consumer Goods, 2 = Financial, 3 = Health Care) and collected salary data. A partial two-way ANOVA table summarizing the results is provided below. Two-way ANOVA: Salary versus Industry, Gender Source MSF P Industry Gender Interaction Error Total DE SS 2 23342.6 1 4915.2 2...
In a random sample of 3,000 non-smckers, 270 suffer from heart disease and, in sample of 800 smokers, 88 suffer from heart disease. At the 0.01 level of significance, test whether the prevalence of heart disease is significantly higher in smokers as compared to non-smokers? [8 markah/marks] (b) Seorang penyelidik ingin membandingkan gaji purata penganalisis kewangan wanita dan lelaki. Seramai 25 orang penganalisis kewangan lelaki dan 16 penganalisis kewangan wanita yang dipilih secara rawak. Gaji purata dan sisihan piawai untuk...
1. ANOVA is a statistical method for verifying the equality between some sample means b. a. some sample standard deviations c. some population standard deviations d some population means Salary information regarding male and female employees of a large company is shown below Sample Size Male (Pop. 1) Female (Pop. 2) 49 47 Sample Mean Salary (in $1,000) , Population Variance 2. The point estimate of the difference μ-μ, between the two population means is Y 7-44-3.0 3. The margin...
answer the exibit with an explanation please
Exhibit 16-1 Salary information regarding male and female employees of a large company is shown below. Mals Female Sample Sure 36 Sample Mean Salary (in $1,000) Population Variance (0) 128 3. Refer to Exhibit 10-1. The point estimate of the difference between the means of the two populations is b. 3 C4 d 4 ANS: B 4. Refer to Exhibit 10-1. The standard error for the difference between the two means is b....
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