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2. Solve for the unknowns a) b) (4x) (3y + 5) X 652 52 I
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D C B In triangle ABC AB = BC = AC ABC is equilateral triangle So, LA = LB = LC = 60° and, Angle DBA + Angle CBA = 180° linea(5) B (3yrs) 65° M520 D. In thiangle BDC LB + LD + LC = 180° LDBL + L BDCA LOLA = 180° → 13y+5)+ 52°+ 90º = 180° -> (@y+5) =Now, Since AB is AB is parallel to co Soi since, L ABD = LBDL [A Alternate interior angles are equal] (43) ° : 52° una 52 x=1

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2. Solve for the unknowns a) b) (4x) (3y + 5) X 652 52 I
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