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1- We need to glue two pieces of metal together to form a bar which will be under a state of stress of: = 100 20 MPa 20 in a

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D Given, stress element 100 [ 20) mo mpa. 20 so where, 120 GO [Tx= 100 Ty = so, Exy=20 ]mpa. 2 Normal stress, Tx, Ty and nor=) Now Reen traction is 3 Tx loo 20 Ty 20 SO 0.5 ch) 96.60 ê + 42.36 êy b) Normal stress, TN = T(h) ñ (15.6012)-(42:32 42-32817h) 1966)2 + (42.36) 105.479 mPa. Ts: d (105.479)² – ( 104.813 11.86 MPa a) Traction force be F, Let be A, then, F = AXTS =

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