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A 4.0-uF parallel-plate capacitor is charged to 6.0-volts. A series RC circuit is then formed using this capacitor, a 3.0-MS

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Answer #1

Capacitance of parallel plats capacitor = 44f Where R= 3Mh = 3x1062 capacitor cho charging equation q=%C1-e les) voltage appltime to qu from initial Let ty = charging charge Now 9 = 9x4X10-6 = 368 166 t2/12 36x10-6 = 48x10-6 (1-e (1 - e-tal 12 ) C 36

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