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Day A bicycle safety organization claims that fatal bicycle accidents are uniformly distributed throughout the week. The tabl

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Answer #1

Answer:

To test,

a)

Ho: The distribution of fatal bicycle accidents throughout the week is uniformly distributed. ( Claim)

H1:The distribution of fatal bicycle accidents throughout the week is not uniformly distributed.

b)

Use \alpha =0.10

d.f= K-1=7-1=6

The critical value for chi-square test :

\chi _{0}^{2}=10.645 ( From Chi-square table)

The rejection region is \chi ^2>\chi _{0}^{2}

c)

Day frequency(O) Expected(E) (oi-Ei) (oi-Ei)^2 (Oi-Ei)^2/Ei
Sunday 109 110.714 -1.714 2.937796 0.026535
Monday 111 110.714 0.286 0.081796 0.000739
Tuesday 105 110.714 -5.714 32.6498 0.294902
Wednesday 112 110.714 1.286 1.653796 0.014938
Thursday 120 110.714 9.286 86.2298 0.778852
Friday 106 110.714 -4.714 22.2218 0.200714
Saturday 112 110.714 1.286 1.653796 0.014938
Total N=775 1.331616
# Expected count=775/7 110.714

Test statistic(\chi ^2)=1.332

Where, \chi ^2 calculated <  \chi ^2tabulated

We accept Ho.

Conclusion: At the 10% significance level, there is not enough evidence to reject the claim that the distribution of fatal bicycle accidents throughout the week is uniformly distributed.

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