Answer:
To test,
a)
Ho: The distribution of fatal bicycle accidents throughout the week is uniformly distributed. ( Claim)
H1:The distribution of fatal bicycle accidents throughout the week is not uniformly distributed.
b)
Use
d.f= K-1=7-1=6
The critical value for chi-square test :
( From Chi-square table)
The rejection region is
c)
Day | frequency(O) | Expected(E) | (oi-Ei) | (oi-Ei)^2 | (Oi-Ei)^2/Ei |
Sunday | 109 | 110.714 | -1.714 | 2.937796 | 0.026535 |
Monday | 111 | 110.714 | 0.286 | 0.081796 | 0.000739 |
Tuesday | 105 | 110.714 | -5.714 | 32.6498 | 0.294902 |
Wednesday | 112 | 110.714 | 1.286 | 1.653796 | 0.014938 |
Thursday | 120 | 110.714 | 9.286 | 86.2298 | 0.778852 |
Friday | 106 | 110.714 | -4.714 | 22.2218 | 0.200714 |
Saturday | 112 | 110.714 | 1.286 | 1.653796 | 0.014938 |
Total | N=775 | 1.331616 | |||
# Expected count=775/7 | 110.714 |
Test statistic()=1.332
Where, calculated < tabulated
We accept Ho.
Conclusion: At the 10% significance level, there is not enough evidence to reject the claim that the distribution of fatal bicycle accidents throughout the week is uniformly distributed.
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