Question

41. Find O! A) 1 B) O C) -1 0 2 E) None of the Above 42. Find P2 A) 120 B) 10 C) 3 D) 20 E) None of the Above 43. Find.cz A) 120 B) 10 C) 3 D) 20 E) None of the Above 44. Find the missing probability. 0 2 1 3 X 4 p(x) 0.12 0.13 0.27 ? 0.09 A) 1 B) 1.61 C) 0.39 D) 0.43 E) None of the Above 45. Find 4! A) 9 B) 24 C) 1 D) 4 E) None of the Above

Answer 1

Solution(41)
We need to calculate 0!
0! = 1
So its correct answer is A. i.e. 1
Solution(42)
We need to calculate 5P2, which can be calculated as
5P2 = 5! / (5-2)! = 5*4*3*2*1/ ( 3*2*1) = 5*4 = 20
So its answer is D. i.e. 20
Solution(43)
We need to calculate 5C2, which can be calculated as
5C2 = 5! / 2! * (5-2)! = 5*4*3*2*1/ (2* 3*2*1) = 5*2 = 10
So its answer is B. i.e. 10
Solution(44)
total probability in a probability distribution is 1
P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) = 1
We need to calculate probability for P(X=3)
P(X=3) = 1- (P(X=0) + P(X=1) + P(X=2) + P(X=4)) = 1 - (0.12+0.13+0.27+0.09) = 1 - 0.61 = 0.39
So its answer is C. i.e. 0.39
Solution(45)
we need to calculate 4!, which can be calculated as
4! = 4*3*2*1 = 24
So its correct answer is B. i.e. 24.