Question

= A magnesium cylinder and a steel ring roll down a slope without slipping on the surface. Both objects have the same mass and outside diameter. The moment of inertia of a cylinder is Icyl mra and the moment of inertia of a ring is Iring m (r2 + rî). Which object will reach the bottom first? 1 1 2 A. The magnesium cylinder will reach the bottom first. B. The steel ring will reach the bottom first. C. They will reach the bottom at the same time.

Answer 1

for Magnesium Cylinder I cyl = mgh for Steel ring Ź m (***072) Iring Both have same mass and game ontas doo diameter. 50, 80=8 Iring Ź m/827032) Iring 7 Icyl angular acceleration, d= Torque Moment of inertia Torque - I L X HI- HI- So, at (i9=80) Here, a is inversely boo bortional toa. Iring is more than I cyl So, acceleration of Cylinder will be more than acceleration of ring. So, Cylinder will do take less time. So, magnesium Cylinder will reach bottom first (A)